Math.hypot() function returns the square root of the sum of squares of its arguments, that is:

Math.hypot ( v 1 , v 2 , , v n ) = i = 1 n v i 2 = v 1 2 + v 2 2 + + v n 2 \mathtt{\operatorname{Math.hypot}(v_1, v_2, \dots, v_n)} = \sqrt{\sum_{i=1}^n v_i^2} = \sqrt{v_1^2 + v_2^2 + \dots + v_n^2}

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句法

Math.hypot([value1[, value2[, ...]]])
					

参数

value1, value2, ...

Numbers.

返回值

The square root of the sum of squares of the given arguments. If at least one of the arguments cannot be converted to a number, NaN 被返回。

描述

Calculating the hypotenuse of a right triangle, or the magnitude of a complex number, uses the formula Math.sqrt(v1*v1 + v2*v2) , where v1 and v2 are the lengths of the triangle's legs, or the complex number's real and complex components.  The corresponding distance in 2 or more dimensions can be calculated by adding more squares under the square root: Math.sqrt(v1*v1 + v2*v2 + v3*v3 + v4*v4) .

This function makes this calculation easier and faster; you simply call Math.hypot(v1, v2) ,或 Math.hypot(v1, v2, v3, v4, ...) .

Math.hypot also avoids overflow/underflow problems if the magnitude of your numbers is very large. The largest number you can represent in JS is Number.MAX_VALUE , which is around 10 308 . If your numbers are larger than about 10 154 , taking the square of them will result in Infinity. For example, Math.sqrt(1e200*1e200 + 1e200*1e200) = Infinity .  If you use hypot() instead, you get better answer: Math.hypot(1e200, 1e200) = 1.4142...e+200 . This is also true with very small numbers. Math.sqrt(1e-200*1e-200 + 1e-200*1e-200) = 0 , but Math.hypot(1e-200, 1e-200) = 1.4142...e-200 .

因为 hypot() is a static method of Math , you always use it as Math.hypot() , rather than as a method of a Math object you created ( Math is not a constructor).

If no arguments are given, the result is +0. If any of the arguments is ±Infinity, the result is Infinity. If any of the arguments is NaN (unless another argument is ±Infinity), the result is NaN. If at least one of the arguments cannot be converted to a number, the result is NaN .

With one argument, Math.hypot() 相当于 Math.abs() .

Polyfill

A naive approach that does not handle overflow/underflow issues:

if (!Math.hypot) Math.hypot = function() {
  var y = 0, i = arguments.length, containsInfinity = false;
  while (i--) {
    var arg = arguments[i];
    if (arg === Infinity || arg === -Infinity)
      containsInfinity = true
    y += arg * arg
  }
  return containsInfinity ? Infinity : Math.sqrt(y)
}
					

A polyfill that avoids underflows and overflows:

if (!Math.hypot) Math.hypot = function () {
  var max = 0;
  var s = 0;
  var containsInfinity = false;
  for (var i = 0; i < arguments.length; ++i) {
    var arg = Math.abs(Number(arguments[i]));
    if (arg === Infinity)
      containsInfinity = true
    if (arg > max) {
      s *= (max / arg) * (max / arg);
      max = arg;
    }
    s += arg === 0 && max === 0 ? 0 : (arg / max) * (arg / max);
  }
  return containsInfinity ? Infinity : (max === 1 / 0 ? 1 / 0 : max * Math.sqrt(s));
};
					

范例

使用 Math.hypot()

Math.hypot(3, 4);          // 5
Math.hypot(3, 4, 5);       // 7.0710678118654755
Math.hypot();              // 0
Math.hypot(NaN);           // NaN
Math.hypot(NaN, Infinity); // Infinity
Math.hypot(3, 4, 'foo');   // NaN, since +'foo' => NaN
Math.hypot(3, 4, '5');     // 7.0710678118654755, +'5' => 5
Math.hypot(-3);            // 3, the same as Math.abs(-3)
					

规范

规范
ECMAScript (ECMA-262)
The definition of 'Math.hypot' in that specification.

浏览器兼容性

更新 GitHub 上的兼容性数据
Desktop Mobile Server
Chrome Edge Firefox Internet Explorer Opera Safari Android webview Chrome for Android Firefox for Android Opera for Android Safari on iOS Samsung Internet Node.js
hypot Chrome 38 Edge 12 Firefox 27 IE No Opera 25 Safari 8 WebView Android 38 Chrome Android 38 Firefox Android 27 Opera Android 25 Safari iOS 8 Samsung Internet Android 3.0 nodejs 0.12

图例

完整支持

完整支持

不支持

不支持

另请参阅

元数据

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